Question

How do you solve `ln(3x)=8.2`?

Answer 1

`color(white)(xx)x=e^(8.2-ln3)`

Explanation:

`color(white)(xx)ln(3x)=8.2`

`=>ln3+lnx=8.2`
`=>ln3+lnx-color(red)ln3=8.2-color(red)ln3`
`=>x=e^(8.2-ln3)`