How do you solve #ln(x^2-x+1)-ln(x-1)+ln(x^2-1)=ln9#?

1 Answer
cspark1981
Nov 1, 2015

# x = 2 #

Explanation:

# ln A + ln B = ln (AB) #
# ln A - ln B = ln (A/B) #

# ln (x^2-x+1) - ln (x−1) + ln (x^2−1) = ln 9 #
# ln (((x^2-x+1)(x^2−1))/(x−1)) = ln 9 #
# ln (((x^2-x+1)(x−1)(x+1))/(x−1)) = ln 9 #
# (x^2-x+1)(x+1) = 9 #
# x^3 = 8 #
# x = 2 #

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