Question

How do you solve `log_11 (y + 8) + log_11 4 = log_11 60`?

Answer 1

`y = 7`

Explanation:

From laws of logs, the log of the sum is the product of the logs.
So left hand side of equation reduces to

`log_11(4y + 32) = log_11(60)`

Now take the anti-log base 11 on both sides to yield:

`4y + 32 = 60`

This is now a normal linear equation in y which may be solved by normal methods to eventually get `y = 7`.