How do you solve #log_2(2x-3)=log_2(x+4)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Noah G Feb 13, 2017 #x = 7#. Explanation: If #log_a b = log_a c#, then #b = c#. #2x - 3= x +4# #2x - x = 4 + 3# #x = 7# Hopefully this helps! Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 2689 views around the world You can reuse this answer Creative Commons License