# How do you solve #Log_2 32 = x#?

##### 2 Answers

Mar 9, 2016

#### Explanation:

The logarithmic expression can be exponentiated with a base of

#2^(log_2 32)=2^x#

The

#32=2^x#

We can write

#2^5=2^x#

Since the bases are equal, we know their powers are also equal, giving:

#x=5#

Mar 9, 2016

#### Explanation:

Since

#log_2 2^5=x#

Using the logarithm rule:

#log(a^b)=b*log(a)#

Giving the equation:

#5*log_2 2=x#

Since

#x=5#