Question

How do you solve `log(2x-8)=4`?

Answer 1

`x={e^4+8}/2 approx 31.3`

Explanation:

(Assuming log base e)

The trick is to rewrite 4 as a logarithm so that the logarithms can be removed. `4=log(e^4)`

`log(2x-8)=4`

`log(2x-8)=log(e^4)`
`2x-8=e^4`

`2x=e^4+8`

`x={e^4+8}/2 approx 31.3`