# How do you solve  log_3 (2x + 1) = log_3 (x - 4)?

##### 1 Answer

We have that

 log_3 (2x + 1) = log_3 (x - 4)=> (2x+1)=(x-4)=>2x-x=-1-4=>x=-5

But hence it should be $x > 4$ there no real solutions.