How do you solve # log_3 (2x + 1) = log_3 (x - 4)#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Konstantinos Michailidis May 7, 2016 We have that # log_3 (2x + 1) = log_3 (x - 4)=> (2x+1)=(x-4)=>2x-x=-1-4=>x=-5# But hence it should be #x>4# there no real solutions. Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 2345 views around the world You can reuse this answer Creative Commons License