# How do you solve log_3 3+log_3x=5?

Apr 16, 2016

$x = 81$

#### Explanation:

You can see straightaway that ${\log}_{3} 3 = 1$, because ${3}^{1} = 3$, so

$1 + {\log}_{3} x = 5$
${\log}_{3} x = 4$

Raise both sides by $3$,

${3}^{{\log}_{3} x} = {3}^{4}$
$x = {3}^{4}$
$x = 81$