# How do you solve m^3 - 2m =m^2 ?

May 11, 2016

${m}^{3} - {m}^{2} - 2 m = 0$

Factor out an $m$

$m \left({m}^{2} - m - 2\right) = 0$

$m \left(m - 2\right) \left(m + 1\right) = 0$

$m = 0 , 2 \mathmr{and} - 1$

Hopefully this helps!