# How do you solve #p( - 5- p ) = 6#?

##### 2 Answers

Mar 22, 2018

#### Explanation:

#"distribute and rearrange into "color(blue)"standard form"#

#rArr-5p-p^2=6#

#rArrp^2+5p+6=0larrcolor(blue)"in standard form"#

#"the factors of + 6 which sum to + 5 are + 3 and + 2"#

#rArr(p+3)(p+2)=0#

#"equate each factor to zero and solve for p"#

#p+3=0rArrp=-3#

#p+2=0rArrp=-2#

Mar 22, 2018

#### Explanation:

Using FOIL method :

Factorization (you can also use quadratic formula and completing square):