Question

How do you solve `p( - 5- p ) = 6`?

Answer 1

`p=-3" or "p=-2`

Explanation:

`"distribute and rearrange into "color(blue)"standard form"`

`rArr-5p-p^2=6`

`rArrp^2+5p+6=0larrcolor(blue)"in standard form"`

`"the factors of + 6 which sum to + 5 are + 3 and + 2"`

`rArr(p+3)(p+2)=0`

`"equate each factor to zero and solve for p"`

`p+3=0rArrp=-3`

`p+2=0rArrp=-2`

Answer 2

`p= -2 and -3`

Explanation:

`p(-5-p)=6`

Using FOIL method :

`-5p-p^2=6`

`p^2+5p+6=0`

Factorization (you can also use quadratic formula and completing square):

`(p+3)(p+2)=0`

`p=-3 and -2`