How do you solve p= sqrt(2p-1)?

Aug 22, 2016

There are two same solutions $p = 1$

Explanation:

$p = \sqrt{2 p - 1}$

or

${p}^{2} = 2 p - 1$

or

${p}^{2} - 2 p + 1 = 0$

or

${\left(p - 1\right)}^{2} = 0$

or

$\left(p - 1\right) \left(p - 1\right) = 0$

or

$p - 1 = 0$

or

$p = 1$

Hence there are two same solutions $p = 1$