# How do you solve (q - 12) 3 <5q + 2?

Jul 12, 2016

$q > - 19$

#### Explanation:

Multiply out the bracket on the left hand side:

$3 \cdot q - 3 \cdot 12 < 5 q + 2$

$3 q - 36 < 5 q + 2$

Subtract $3 q$ from both sides of the inequality:

$- 36 < 2 q + 2$

Subtract 2 from both sides of the inequality:

$- 38 < 2 q$

Divide both sides by 2

$- 19 < q$

So our solution is that $q > - 19$