How do you solve #r^2=14r#?

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Answer 1 · 2017-09-29T15:03:48

See a solution process below:

First, subtract #color(red)(14r)# from each side of the equation to equate to #0# while keeping the equation balanced:

#r^2 - color(red)(14r) = 14r - color(red)(14r)#

#r^2 - 14r = 0#

Next, factor an #r# out from each term on the left side of the equation:

#(r * r) - (14 * r) = 0#

#r(r - 14) = 0#

Now, solve each term on the left side of the equation for #0# to find the solutions:

Solution 1:

#r = 0#

Solution 2:

#r - 14 = 0#

#r - 14 + color(red)(14) = 0 + color(red)(14)#

#r - 0 = 14#

#r = 14#

The Solutions Are: #r = 0# and #r = 14#