How do you solve #root3(4x)+11=5#?

1 Answer
Dec 21, 2016

Answer:

The answer is #x=-54#

Explanation:

Here is how you go about solving this problem:

#1.# The goal in questions like this is to isolate the variable you're trying to solve for.

#2.# So we start with subtracting #11# from both sides, so you get:

#root(3)4x =-6#

#3.# The next step is to get rid of the cube root. the way to do that is simply by raising both sides to the power of 3. notice that you canNOT simply go ahead and divide both sides by 4 and THEN get rid of the cube root. That is because #4x# is under the cube root and you should "free up the #4x#" from the cube root before you can divide by #4#. be aware of that so here is what it will look like:

#(root(3)4x)^3 =(-6)^3#

#4x = (-6)^3#

#4x = -216#

#4.# Finally we divide both sides by 4 to get #x# by itself:

#x = -216/4#

#x = -54#

Hope this helped (c: