# How do you solve root3(x+4)=root3(2x-5)?

Mar 29, 2017

$x = 9$

#### Explanation:

$\sqrt[3]{x + 4} = \sqrt[3]{2 x - 5}$

power of 3 to both sides.
${\left(\sqrt[3]{x + 4}\right)}^{3} = {\left(\sqrt[3]{2 x - 5}\right)}^{3}$

$x + 4 = 2 x - 5$
$9 = x$