How do you solve root3x -4 = 2?

May 2, 2016

$x = 216$

Explanation:

$\sqrt[3]{x} + 0 = 2 + 4$

$\sqrt[3]{x} = 6$

Example: ${\left(\sqrt{4}\right)}^{2} = 4$ In squaring the square root I have reversed the process of square rooting 4

Using the above method

Cube both sides

$x = {6}^{3}$

$x = 216$