# How do you solve root4(2x)-13=-9?

Apr 25, 2017

$x = 128$

#### Explanation:

$\sqrt[4]{2 x} - 13 = - 9$

Add $13$ to both sides

$\sqrt[4]{2 x} \cancel{- 13} \cancel{+ 13} = - 9 + 13$

$\sqrt[4]{2 x} = 4$

Now we are going to raise both sides of the equation to the power of $4$ so we can get rid of that $\text{root} 4$

${\left(\sqrt[4]{2 x}\right)}^{4} = {\left(4\right)}^{4}$

[Exponent cancels with root of equal power]

$2 x = 256$

Divide both sides by $2$

$\frac{2 x}{2} = \frac{256}{2}$

$\frac{\cancel{2} x}{\cancel{2}} = \frac{256}{2}$

$x = 128$