How do you solve #root4(2x)-13=-9#?

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Answer 1 · 2017-04-25T13:17:54

#x=128#

#root4(2x)-13=-9#

Add #13# to both sides

#root4(2x)cancel(-13)cancel(+13)=-9+13#

#root4(2x)=4#

Now we are going to raise both sides of the equation to the power of #4# so we can get rid of that #"root" 4#

#(root4(2x))^4=(4)^4#

[Exponent cancels with root of equal power]

#2x=256#

Divide both sides by #2#

#(2x)/2=256/2#

#(cancel2x)/cancel2=256/2#

#x=128#