How do you solve root4(3t)-2=0?

Feb 26, 2017

$5 \frac{1}{3}$

Explanation:

$\sqrt[4]{3 t} - 2 = 0$

$\sqrt[4]{3 t} = 2$

Put to the power of four on both sides
(cause $\sqrt[4]{3 t} = 3 {t}^{\frac{1}{4}}$ and to the power of four $3 {t}^{\left(\frac{1}{4}\right) \cdot 4} = 3 t$)

$3 t = {2}^{4}$

$3 t = 16$

$t = \frac{16}{3} = 5 \frac{1}{3}$