# How do you solve root4(x-7)=2?

May 13, 2016

$x = 23$

#### Explanation:

Given:

$\sqrt[4]{x - 7} = 2$

Raise both sides to the $4$th power to get:

$x - 7 = 16$

Add $7$ to both sides to find:

$x = 23$

Check:

$\sqrt[4]{23 - 7} = \sqrt[4]{16} = \sqrt[4]{{2}^{4}} = 2$