# How do you solve root5(2x+1)+5=9?

Sep 12, 2016

$x = 511.5$

#### Explanation:

$\sqrt[5]{2 x + 1} + 5 = 9 \text{ } \leftarrow$ isolate the term with x

$\sqrt[5]{2 x + 1} = 9 - 5$

$\sqrt[5]{2 x + 1} = 4 \text{ } \leftarrow$ raise both sides to the power of 5

${\left(\sqrt[5]{2 x + 1}\right)}^{5} = {4}^{5} \text{ } \leftarrow {\left(\sqrt[5]{x}\right)}^{5} = x$

$2 x + 1 = 1024$

$2 x = 1023$

$x = 511.5$