# How do you prove secx-cosx=secxsinx?

$\frac{1}{\cos} x - \cos x \ne \frac{1}{\cos} x \times \sin x$
$\frac{1 - {\cos}^{2} x}{\cos} x \ne \sin \frac{x}{\cos} x$
${\sin}^{2} \frac{x}{\cos} x \ne \sin \frac{x}{\cos} x$