How do you solve #sin(3x)=-1# and find all exact general solutions?

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Answer 1 · 2016-10-29T15:12:59

#sin(3x) = -1 -> 3x = sin^-1(-1)#

#3x = (3pi)/2 + 2pin#

#x = pi/2 + (2pin)/3#

#x = (3pi + 4pin)/6#

Practice Exercises:

a) #cos(2x) = -sqrt(3)/2#

b) #tan(4x) = -1#

Hopefully this helps!