How do you solve #sqrt(1-3x)=-7#?

2 Answers
Jul 22, 2015

Answer:

There is no solution to the given equation.

Explanation:

The definition of the square root symbol is such that its value is always non-negative.

Therefore #sqrt("anything") != "negative value"#

Jul 22, 2015

Answer:

I found: NO real solutions!

Explanation:

You may square both sides to get:
#(sqrt(1-3x))^2=(-7)^2#
#1-3x=49#
#-3x=48#
#x=-16#
checking it by substituting back into the original equation:
#sqrt(1-3(-16))=-7#
#sqrt(49)=-7#
#7=-7# NOT TRUE!!!