Question

How do you solve `sqrt(1-3x)=-7`?

Answer 1

There is no solution to the given equation.

Explanation:

The definition of the square root symbol is such that its value is always non-negative.

Therefore `sqrt("anything") != "negative value"`

Answer 2

I found: NO real solutions!

Explanation:

You may square both sides to get:
`(sqrt(1-3x))^2=(-7)^2`
`1-3x=49`
`-3x=48`
`x=-16`
checking it by substituting back into the original equation:
`sqrt(1-3(-16))=-7`
`sqrt(49)=-7`
`7=-7` NOT TRUE!!!