# How do you solve sqrt(1-3x)=-7?

Jul 22, 2015

There is no solution to the given equation.

#### Explanation:

The definition of the square root symbol is such that its value is always non-negative.

Therefore sqrt("anything") != "negative value"

Jul 22, 2015

I found: NO real solutions!

#### Explanation:

You may square both sides to get:
${\left(\sqrt{1 - 3 x}\right)}^{2} = {\left(- 7\right)}^{2}$
$1 - 3 x = 49$
$- 3 x = 48$
$x = - 16$
checking it by substituting back into the original equation:
$\sqrt{1 - 3 \left(- 16\right)} = - 7$
$\sqrt{49} = - 7$
$7 = - 7$ NOT TRUE!!!