How do you solve #sqrt(-10+7p)=p#?

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Answer 1 · 2017-02-14T04:00:21

#p=2# or #p=5#

#sqrt(-10+7p)=p#

Square both sides.

#-10+7p=p^2#

Subtract #p^2# from both sides and order the equation.

#-p^2+7p-10=0#

Multiply all terms by #-1#.

#p^2-7p+10=0#

Factorise.

#p^2-5p-2p+10=0#

#p(p-5)-2(p-5)=0#

#(p-2)(p-5)=0#

#p-2=0# or #p-5=0#

#p=2# or #p=5#