How do you solve #sqrt(10h)+1=21# and check your solution?

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Answer 1 · 2018-07-11T01:28:44

I tried this:

Let us rearrange it and write:

#sqrt(10h)=21-1#

#sqrt(10h)=20#

square both sides:

#(sqrt(10h))^2=20^2#

#10h=400#

and:

#h=400/10=40#

let us use this result in our original equation:

#sqrt(10*40)+1=21#

#sqrt(400)+1=21#

#20+1=21# YES

Answer 2 · 2018-07-11T01:30:08

#h=40#

#sqrt(10h)+1=21#

#sqrt(10h)=20#

#10h=20^2#

#10h=400#

#h=40#

To check your solution, sub #h=40# back into your equation

LHS
=#sqrt(10h)+1#
=#sqrt(10times40)+1#
=#20+1#
=#21#
=RHS

Therefore, when #h=40#, the equation is true