How do you solve # sqrt(2x –3) = 2#?

2 Answers
Apr 19, 2018

Answer:

See below

Explanation:

Squaring both sides of equation we have

#(sqrt(2x-3))^2=2^2#

#2x-3=4#

#2x=7#

#x=7/2#

Now check if it is a valid solution

#sqrt(2·7/2-3)=sqrt(7-3)=sqrt4=2#

Is a valid solution and our equation is now solved

Apr 19, 2018

Answer:

#x=7/2#

Explanation:

#color(blue)"square both sides"#

#(sqrt(2x-3))^2=2^2#

#rArr2x-3=4#

#"add 3 to both sides and divide by 2"#

#rArr2x=7rArrx=7/2#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#sqrt(2xx7/2-3)=sqrt(7-3)=sqrt4=2=" right side"#

#rArrx=7/2" is the solution"#