# How do you solve #sqrt(2x+3)=6#?

##### 2 Answers

#### Explanation:

#color(blue)"square both sides"#

#(sqrt(2x+3))^2=6^2#

#2x+3=36#

#"subtract 3 from both sides"#

#2x=36-3=33#

#"divide both sides by 2"#

#x=33/2#

#color(blue)"As a check"#

#sqrt(2xx33/2+3)=sqrt(33+3)=sqrt36=6larr"correct"#

See a solution process below:

#### Explanation:

First, square both sides of the equation to eliminate the radical while keeping the equation balanced::

Next, subtract

Now, divide each side of the equation by