How do you solve #sqrt(2x + 7) = 6#?

1 Answer
Apr 12, 2018

Answer:

#x=29/2#

Explanation:

#color(blue)"square both sides"#

#rArr(sqrt(2x+7))^2=6^2#

#rArr2x+7=36#

#"subtract 7 from both sides"#

#rArr2x=29rArrx=29/2#

#color(blue)"As a check"#

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#sqrt(29+7)=sqrt36=6=" right side"#

#rArrx=29/2" is the solution"#