How do you solve \sqrt { - 32- 12x } = x?

Jun 9, 2018

No real solutions

Explanation:

After squaring we get

$0 = {x}^{2} + 12 x + 32$
${x}_{1 , 2} = - 6 \pm 2$
so we get

${x}_{1} = - 4$
${x}_{2} = - 8$
which are no Solutions since we have $x \ge 0.$