How do you solve # sqrt(3x+10) = x+2#?

2 Answers
Aug 13, 2016

Answer:

#x = -3 or +2#

Explanation:

#sqrt(3x+10) = x+2#

Square both sides:
#3x+10 = (x+2)^2#

#3x+10 = x^2 + 4x +4#

#x^2+x-6=0#

#(x+3)(x-2) = 0#

Therefore:

Either #(x+3)= 0 -> x=-3#
Or #(x-2) = 0 -> x=+2#

Aug 13, 2016

Answer:

#x=2 or x=-3#

Explanation:

#sqrt(3x+10)=x+2# ; squaring both sides #3x+10=(x+2)^2 or x^2+4x+4-3x-10=0 orx^2+x-6=0 or x^2+3x-2x-6=0 or x(x+3)-2(x+3)=0 or(x+3)(x-2)=0 :. x+3=0 or x=-3; x-2=0 or x=2#[Ans]