# How do you solve \sqrt { 3x - 22} = \sqrt { 10- x }?

Nov 14, 2016

$x = 8$

#### Explanation:

We need to get rid of the radicals (square roots), so square both sides.

${\left(\sqrt{3 x - 22}\right)}^{2} = {\left(\sqrt{10 - x}\right)}^{2}$

Now we have, which is much easier to deal with

$3 x - 22 = 10 - x$

Add the variable $x$ to both sides.

$4 x - 22 = 10$

Add $22$ to both sides.

$4 x = 32$

Divide both sides by $4$ to isolate $x$

$x = 8$

Hope that helps!