# How do you solve sqrt(4m^2-3m+2)-2m-5=0?

Feb 10, 2017

$m = 1$

#### Explanation:

If we separate out the root and put everything else on the other side of the = we can 'get rid' of the root by squaring both sides.

Write as $\sqrt{4 {m}^{2} - 3 m + 2} = 2 m + 5$

Square both sides

$4 {m}^{2} - 3 m + 2 \text{ "=" } {\left(2 m + 5\right)}^{2}$

$\cancel{4 {m}^{2}} - 3 m + 2 \text{ "=" } \cancel{4 {m}^{2}} + 20 m + 25$

$20 m + 3 m = 2 - 25$

$23 m = 23$

Divide both sides by 23

$m = 1$