How do you solve #sqrt(4m^2-3m+2)-2m-5=0#?

1 Answer
Feb 10, 2017

Answer:

#m=1#

Explanation:

If we separate out the root and put everything else on the other side of the = we can 'get rid' of the root by squaring both sides.

Write as #sqrt(4m^2-3m+2)=2m+5#

Square both sides

#4m^2-3m+2" "=" "(2m+5)^2#

#cancel(4m^2)-3m+2" "=" "cancel(4m^2)+20m+25#

#20m+3m=2-25#

#23m=23#

Divide both sides by 23

#m=1#