How do you solve #sqrt(4x+8)+8 = 1#?

2 Answers
May 6, 2018

Answer:

#x = 10.25#

Explanation:

#sqrt(4x+8) = 1 - 8#
#sqrt(4x+8) = -7#
#(sqrt(4x+8))^2 = (-7)^2#
#4x+8 = 49#
#4x = 41#
#(4x) / 4= 41 / 4#
#x = 41 / 4#
#x = 10.25#

May 6, 2018

Answer:

#"no solution"#

Explanation:

#"isolate "sqrt(4x+8)" by subtracting 8 from both sides"#

#rArrsqrt(4x+8)=-7#

#sqrt(4x+8)>=0to x inRR#

#rArr"there is no solution"#