How do you solve #sqrt(6 x + 5)=sqrt 53#?

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Answer 1 · 2015-08-06T06:18:21

#color(blue)(x=8#

#sqrt(6x+5) = sqrt53#

Squaring both sides

#(sqrt(6x+5))^2 = (sqrt53)^2#

#6x+5 = 53#

#6x = 53-5#

#6x = 48#

#x=48/6 #

#color(blue)(x= 8#