# How do you solve \sqrt { 6x - 4} = \sqrt { 3}?

Apr 12, 2018

$x = \frac{7}{6}$

#### Explanation:

$\sqrt{6 x - 4} = \sqrt{3}$

$6 x - 4 = 3 \text{ }$ Square both sides to cancel the radicals

$6 x = 7 \text{ }$ Add $4$ to both sides

$x = \frac{7}{6} \text{ }$ Divide both sides by $6$