# How do you solve #sqrt(6x-5)+10=3#?

##### 2 Answers

See the entire solution process below:

#### Explanation:

First, subtract

Next, square both sides to eliminate the radical while keeping the equation balanced:

Then, add

Now, divide each side of the equation by

no solution.

#### Explanation:

#color(blue)"Isolate the square root"# by subtracting 10 from both sides.

#sqrt(6x-5)cancel(+10)cancel(-10)=3-10#

#rArrsqrt(6x-5)=-7#

#color(blue)"square both sides"#

#(sqrt(6x-5))^2=(-7)^2#

#rArr6x-5=49# add 5 to both sides.

#6xcancel(-5)cancel(+5)=49+5#

#rArr6x=54# divide both sides by 6

#(cancel(6) x)/cancel(6)=54/6#

#rArrx=9#

#color(blue)"As a check"# Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

#"left side "=sqrt((6xx9)-5)+10#

#=color(white)(left side)=sqrt49+10#

#=color(white)("left side)=7+10#

#color(white)(xxxxxxxx)=17!=3#

#rArr" there is no solution"#