Question

How do you solve `sqrt(7 - 3x) = 1`?

Answer 1

`x = 2`

Explanation:

`sqrt(7-3x) = 1`

`sqrt(7-3x)^2 = 1^2`

`7-3x = 1`

`7-3x-7=1-7`

`-3x = -6`

`3x = 6`

`(3x)/3 = 6/3`

`x = 2`