# How do you solve sqrt(7x-6)=x?

$\sqrt{7 x - 6} = x \implies 7 x - 6 = {x}^{2} \implies 0 = {x}^{2} - 7 x + 6$
Therefore  0= (x-6)*(x-1)
One of them is (x-6)=0 $\implies$ x=6
And the other one is (x-1)=0 $\implies$ x=1