Question

How do you solve `sqrt(7x-6)=x`?

Answer 1

`sqrt(7x-6) = x => 7x-6 = x^2 => 0= x^2-7x+6`
Therefore # 0= (x-6)*(x-1)#

So there will be two result of x;
One of them is (x-6)=0 `=>` x=6
And the other one is (x-1)=0 `=>` x=1