# How do you solve sqrt(8-x)+6=4?

Aug 11, 2015

$\sqrt{8 - x} + 6 = 4$ has no Real solutions
$\sqrt{\text{anything}} \ge 0$
$\textcolor{w h i t e}{\text{XXXX}}$(by definition/convention)
If $\sqrt{x - 8} + 6 = 4$
$\textcolor{w h i t e}{\text{XXXXXXXX}}$$\rightarrow$$\textcolor{w h i t e}{\text{XXXX}}$$\sqrt{8 - x} = - 2 < 0$