Question

How do you solve `sqrt(k+9)-sqrtk=sqrt3`?

Answer 1

`k = 3`

Explanation:

The feasibility conditions are

`k+9 ge 0` and `k ge 0` so `rArr k ge 0`

so by inspection, the solution is for `k=3` because then

`sqrt(3+9)-sqrt3=sqrt3` or

`sqrt(4 xx 3) = 2sqrt3=sqrt3+sqrt3`