# How do you solve sqrt (m) + 7 = 5?

Sep 11, 2015

Using the non-primary root, it could be argued that $m = 4$

#### Explanation:

$\sqrt{m} + 7 = 5$

$\Rightarrow \sqrt{m} = - 2$

Since the primary square root is positive
this has no Real solution using the primary root.

However if we allow secondary roots:
$\textcolor{w h i t e}{\text{XXX}}$square root of $m = \pm \sqrt{m}$
and
for $m = 4$,
$\textcolor{w h i t e}{\text{XXX}}$one solution is
$\textcolor{w h i t e}{\text{XXX}}$square root of $m = - \sqrt{4} = - 2$

The most likely, expected answer is that the given equation has no valid solution (in $\mathbb{R}$)