# How do you solve #sqrt(u+6)=u# and check your solution?

##### 1 Answer

Jul 13, 2017

#### Answer:

#### Explanation:

There are two possibilities:

To check your solutions, substitute them back into the original equation.

#sqrt(u+6)=u#

#sqrt(3+6)=3#

#sqrt(9)=3#

#3=3# #-># works

#sqrt(u+6)=u#

#sqrt(-2+6)=-2#

#sqrt(4)=-2#

#2=-2# #-># does not work

So, the only solution is