How do you solve #sqrt(x+1) = 2#?

2 Answers
Jun 2, 2016

Answer:

x = 3

Explanation:

To 'undo' the square root we have to perform the inverse operation.
The inverse to 'square root' is 'square'. Since this is an equation we must square both sides.

#rArr(sqrt(x+1))^2=2^2rArrx+1=4rArrx=4-1=3#

Jun 2, 2016

Answer:

#x = 3#

Explanation:

When #sqrt(x + 1) = 2#
Square both sides
#x + 1 = 4#
Subtract #1# from both sides
#x = 3#

Check when #x = 3#
#3 + 1 = 4# and #sqrt 4 = 2#
So answer is correct