How do you solve #sqrt(x+1)-7=0#?

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Answer 1 · 2016-04-10T13:37:33

#x=48#

Our aim is to find the value of #x#

#color(blue)(sqrt(x+1)-7=0#

Add #7# both sides

#rarrsqrt(x+1)cancel(-7+7)=0+7#

#rarrsqrt(x+1)=7#

Square both sides to get rid of the radical sign (#sqrt#)

#rarr(sqrt(x+1))=7^2#

#rarrx+1=49#

Subtract #1# both sides

#rarrxcancel(+1-1)=49-1#

#color(green)(rArrx=48#