# How do you solve sqrt(x+1)-7=0?

Apr 10, 2016

$x = 48$

#### Explanation:

Our aim is to find the value of $x$

color(blue)(sqrt(x+1)-7=0

Add $7$ both sides

$\rightarrow \sqrt{x + 1} \cancel{- 7 + 7} = 0 + 7$

$\rightarrow \sqrt{x + 1} = 7$

Square both sides to get rid of the radical sign (sqrt)

$\rightarrow \left(\sqrt{x + 1}\right) = {7}^{2}$

$\rightarrow x + 1 = 49$

Subtract $1$ both sides

$\rightarrow x \cancel{+ 1 - 1} = 49 - 1$

color(green)(rArrx=48