# How do you solve sqrt(x+1) = 8?

Apr 10, 2016

x=63

#### Explanation:

$\sqrt{x + 1} = 8$
Now you have to square both sides to cencle out root.

${\left(\sqrt{x + 1}\right)}^{2} = {8}^{2}$
$x + 1 = 64$
$x = 64 - 1$
$x = 63$

In order to verify: $\sqrt{63 + 1} = 8$
$\sqrt{64} = 8$
$\pm 8 = 8$
In the verification $\pm$ is just because of the rule any number squared gives a positive value. Accordingly ${\left(- 8\right)}^{2} = 64$ as well as ${8}^{2} = 64$.

The previous answer was not correct.