Question

How do you solve `sqrt(x+16)=sqrtx+4`?

Answer 1

I got `x=0`

Explanation:

We can square both sides:
`(sqrt(x+16))^2=(sqrt(x)+4)^2`
`x+16=x+8sqrt(x)+16`
rearrange:
`cancel(x)cancel(+16)=cancel(x)+8sqrt(x)cancel(+16)`
so:
`8sqrt(x)=0`
and:
`x=0`