How do you solve #sqrt(x-2)=4#?
1 Answer
Jun 4, 2018
Explanation:
#color(blue)"square both sides"#
#(sqrt(x-2))^2=4^2#
#x-2=16#
#"add 2 to both sides"#
#x=16+2=18#
#color(blue)"As a check"#
#sqrt(18-2)=sqrt16=4=" right side"#
#x=18" is the solution"#
