How do you solve #sqrt(x+20)-x=0#?

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Answer 1 · 2016-04-12T19:28:42

#x={-4,5}#

#sqrt(x+20)-x=0#

#sqrt(x+20)=x#

#(sqrt(x+20))^2=x^2#

#x+20=x^2#

#x^2-x-20=0#

#(x-5)(x+4)=0#

#if (x-5)=0" then "x=5#

#if (x+4)=0" then "x=-4#

#x={-4,5}#