How do you solve #sqrt(x-5) = 2sqrt6#?

2 Answers
May 25, 2016

Answer:

#x=29#

Explanation:

Square both sides.

#(sqrt(x-5))^2=(2sqrt6)^2#

On the left side, the square root and the exponent of #2# undo one another, leaving just #x-5#.

On the right side, to square #2sqrt6#, we see that #(2sqrt6)^2=2^2*(sqrt6)^2=4*6=24#.

#x-5=24#

#x=29#

May 25, 2016

Answer:

#x = 29#

Explanation:

square both sides
#x - 5 = (2sqrt6)^2 -> x - 5 = 2^2 xx 6 -> x - 5 = 24#
add 5 to both sides
#x = 29#