How do you solve #sqrt(x-6)=sqrt(1/3x)=0#?

1 Answer
Alan P.
Sep 4, 2016

No value of #x# satisfies both equalities.

Explanation:

#sqrt(x-6)=sqrt(1/3x)#
#color(white)("XXX")rarrx-6=1/3x#

#color(white)("XXX")rarr3x-18=x#

#color(white)("XXX")rarr2x=18#
#color(white)("XXX")rarrx=9#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#sqrt(1/3x)=0#
#color(white)("XXX")rarrx=0#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#sqrt(x-6)=0#
#color(white)("XXX")rarrx-6=0#

#color(white)("XXX")rarrx=6#

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